x^2-5/3x+c=0

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Solution for x^2-5/3x+c=0 equation: 


x in (-oo:+oo)

c+x^2-((5/3)*x) = 0

c+x^2+(-5/3)*x = 0

c+x^2-5/3*x = 0

DELTA = (-5/3)^2-(1*4*c)

DELTA = 25/9-4*c

25/9-4*c = 0

25/9-4*c = 0 // - 25/9

-4*c = -25/9 // : -4

c = -25/9/(-4)

c = 25/36

DELTA = 0  <=>  t_1 = 25/36

x = 5/3/(1*2) i c = 25/36

x = 5/6 i c = 25/36

( x = ((25/9-4*c)^(1/2)+5/3)/(1*2) or x = (5/3-(25/9-4*c)^(1/2))/(1*2) ) i c > 25/36

( x = ((25/9-4*c)^(1/2)+5/3)/2 or x = (5/3-(25/9-4*c)^(1/2))/2 ) i c > 25/36

c-25/36 > 0

c-25/36 > 0 // + 25/36

c > 25/36

x in { 5/6, ((25/9-4*c)^(1/2)+5/3)/2, (5/3-(25/9-4*c)^(1/2))/2 }

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